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Which of the following is a solution to the equation x[tex]x^{2}[/tex]– 6x + 5 = 0?

Sagot :

Ujalakhan18idn

Answer:

[tex]\huge\boxed{\sf x =5 \ \ \ OR \ \ \ x = 1}[/tex]

Step-by-step explanation:

Given equation:

[tex]x^2-6x+5=0[/tex]

Using mid-term break formula

  • Multiply -5 and -1 gives +5 (side term) and adding them gives -6 (mid term).
  • So, split -6 into -5 and -1

[tex]x^2-5x-x+5=0\\\\Take \ common\\\\x(x-5)-1(x-5)=0\\\\Take \ (x-5) \ common\\\\(x-5)(x-1)=0[/tex]

Either,

x - 5 = 0         OR         x - 1 = 0

x = 5           OR       x = 1

[tex]\rule[225]{225}{2}[/tex]

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