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If you had 6 mol of oxygen and 12 mol of mercury, what would be the limiting reactant? show your work

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Eduard22slyidn

The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)

Balanced equation

4Hg + O₂ —> 2Hg₂O

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

How to determine the limiting reactant

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

Therefore,

12 moles of Hg will react with = 12 / 4 = 3 moles of O₂

From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.

Thus, Hg is the limiting reactant and O₂ is the excess reactant .

Learn more about stoichiometry:

https://brainly.com/question/14735801

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