Allisongrentidn
Answered

Explore a world of knowledge and get your questions answered on IDNLearn.com. Get accurate and detailed answers to your questions from our dedicated community members who are always ready to help.

The cutoff frequency for a certain element is 1.22 x 1015 Hz. What is its work function in eV?
Hint: 1 eV 1.60 x 10-19 J
=[?] eV

someone please teach me how to solve this its gonna make me cry

The Cutoff Frequency For A Certain Element Is 122 X 1015 Hz What Is Its Work Function In EV Hint 1 EV 160 X 1019 J EV Someone Please Teach Me How To Solve This class=

Sagot :

Pstnonsonjokuidn

The work function of the metal is obtained as 5.1 eV

What is the cutoff frequency?

The cutoff frequency is the frequency below which photo electric effect can not occur as electrons are not removed from the metal surface.

Now;

fo = 1.22 x 10^15 Hz

Wo = hfo

Wo = 6.6 * 10^-34 * 1.22 x 10^15

Wo = 8.1 * 10^-19 J

If 1 eV = 1.60 x 10-19 J

x eV = 8.1 * 10^-19 J

x = 8.1 * 10^-19/ 1.60 x 10-19

x = 5.1 eV

Learn more about cutoff frequency:https://brainly.com/question/14378802

#SPJ1

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.