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how do you solve this pls

How Do You Solve This Pls class=

Sagot :

Step-by-step explanation:

The equation of a exponential function is

[tex]a \times (b) {}^{x} [/tex]

where a is the y value of the y intercept, b is the constant rate of change.

Here the y intercept is (0,4), the y value of the y intercept is 4.

So a=4

The graph passes through point (1,2) so

[tex]h(x) = 4 \times b {}^{x} [/tex]

Plug in 1 for x, 2 for h(x)

[tex]2 = 4 \times {b}^{1} [/tex]

Anything to the first power is itself so

[tex]2 = 4 \times b[/tex]

Isolate b.

[tex] \frac{1}{2} = b[/tex]

So our function is

[tex]4 \times ( \frac{1}{2} ) {}^{x} [/tex]

Answer:

[tex]h(x)=4\left(\dfrac{1}{2}\right)^x[/tex]

Step-by-step explanation:

Exponential Function

General form of an exponential function: [tex]f(x)=ab^x[/tex]

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

From inspection of the given diagram, the defined points on the curve are:

  • (0, 4)
  • (1, 2)

As one of the defined points is the y-intercept:

[tex]\implies a=4[/tex]

Substitute the found value of a and the point (1, 2) into the general form of an exponential function and solve for b:

[tex]\begin{aligned}h(x)=ab^x & \\\implies h(1)=4b^1 & = 2\\4b & = 2\\b & = \dfrac{2}{4}\\b & =\dfrac{1}{2} \end{aligned}[/tex]

Finally, substitute the found values of a and b to complete the equation for h(x):

[tex]\implies h(x)=4\left(\dfrac{1}{2}\right)^x[/tex]

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