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Sagot :
a) p₀ = 1.2 kg m / s
b) p_f = 1.2 kg m / s
c) [tex]v_{2f}[/tex] = 1.278 m/s
d)1.2482 =[tex]v_{2f}[/tex] cos θ
e) 0.2736 =[tex]v_{2f}[/tex]sin θ
g) θ = 12.36
What is momentum?
Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.
According to the question,
We define a system formed by the two balls, which are isolated and the forces during the collision are internal.
Hence , the momentum is conserved
a) The momentum of the system before the collision:
[tex]p_o = m v_1_0 + 0 p_o= 0.6 2 p_o = 1.2 kg m / s[/tex]
b) The momentum of the system after the collision, as the system is isolated, the momentum is conserved so
[tex]p_f = 1.2 kg m / s[/tex]
d. On X axis
[tex]p_ox[/tex] = 1.2 kg m / s
[tex]p_{fx}[/tex]= m v1f cos 20 + m v2f cos θ
[tex]p_o = p_f[/tex]
1.2 = 0.6 (-0.8) cos 20+ 0.6[tex]v_{2f}[/tex] cos θ
1.2482 =[tex]v_{2f}[/tex] cos θ
e. On Y axis
[tex]p_{oy} = 0[/tex]
[tex]p_{fy}[/tex]= m[tex]v_{1f}[/tex]sin 20 + m[tex]v_{2f}[/tex]cos θ
0 = 0.6 (-0.8) sin 20 + 0.6 [tex]v_{2f}[/tex] sin θ
0.2736 =[tex]v_{2f}[/tex]sin θ
Here,
g. we write our system of equations
0.2736 =[tex]v_{2f}[/tex] sin θ
1.2482 = [tex]v_{2f}[/tex] cos θ
0.219 = tan θ (divide)
θ = tan⁻¹ 0.21919
θ = 12.36
c. Now To find the velocity
0.2736 = [tex]v_{2f}[/tex] sin θ
[tex]v_{2f}[/tex]= 0.2736 / sin 12.36
[tex]v_{2f}[/tex] = 1.278 m / s
Learn more about momentum here:
https://brainly.com/question/4956182
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