Solve the problem.
The length of a rectangular room is 9 feet longer than twice the width. If the room's perimeter is
198 feet, what are the room's dimensions?

Question

03-07-2022
Mathematics

Answered

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Solve the problem.
The length of a rectangular room is 9 feet longer than twice the width. If the room's perimeter is
198 feet, what are the room's dimensions?

Sagot :

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E348779760idn E348779760idn · Answer 1 · 2022-07-04T16:58:58-04:00

Answer:

width is 30, and the length 69.

Step-by-step explanation:

In order to do this, we need to do ALGOOBRAA

lets say x is equal to the width of the room

then, that means the length is (9+2x) Sooooo,

198=2x+2(9+2x)

Using the distributive property, we know that

2(9+2x)=18+4x

If you dont know what that is, then go search it up :/

so,

198=2x+18+4x

198=6x+18

180=6x

30=x

BAM

Now, we know that the width is 30, bro.

That means the length is 60+9, Which is 69.

Therefore, the width is 30, and the length 69.

Sry if im wrong btw.

AshishdwivedilVTidn AshishdwivedilVTidn · Answer 2 · 2022-07-05T03:32:45-04:00

The width of rectangle is 30, and the length is 69.

What is Rectangle?

A rectangle is a quadrilateral. The opposite sides of a rectangle are equal and parallel to each other. The interior angle of a rectangle at each vertex is 90°. The sum of all interior angles is 360°. The diagonals bisect each other.

Here, lets say x is equal to the width of the room

then, that means the length is (9+2x) So,

198 = 2x+2(9+2x)

Using the distributive property, we know that

2(9+2x)=18+4x

If you don't know what that is, then go search it up :/

so,

198 = 2x+18+4x

198=6x+18

180=6x

30=x

Now, we know that the width is 30,

That means the length is 60+9, Which is 69.

Thus, the width of rectangle is 30, and the length is 69.

Learn more about Rectangle from:

https://brainly.com/question/15019502

#SPJ1

Sagot :

What is Rectangle?

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