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What is the probabily of the 90th percentile given mean of 262 and a standard deviation of 45

Sagot :

The probability of the 90th percentile given a mean of 262 and a standard deviation of 45 is 319.672

Here,

The formula for the percentile probability is

[tex]P=\mu+z\sigma[/tex]

P=262 + 1.2816(45)

P = 319.672

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