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A building in a city has a rectangular base. the length of the base measures 65 ft less than twice the width. the perimeter of this base is 890 ft. what are the dimensions of the base? the width of the base is ft.

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By solving a system of equations, we will see that the width is 170ft and the length 275 ft.

How to get the dimensions of the base?

For a rectangle of length x and width y, the perimeter is:

P = 2*(x + y).

Here we know that:

x = 2y - 65ft

p = 890ft = 2(x + y)

So we have a system of equations.

To solve this, we need to replace the first equation into the second one:

890ft = 2(x + y)

890ft = 2(( 2y - 65ft) + y)

Now we can solve this for y.

890ft = 4y - 130ft + 2y

890ft + 130ft = 6y

1020ft/6 = y = 170ft

So the width is 170ft, and we know that:

x = 2y - 65ft = 2*(170ft) - 65ft = 275ft

So the length is 275 ft.

If you want to learn more about systems of equations:

https://brainly.com/question/13729904

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