#5 In triangle ABC, AB = 9 and BC = 15. What is the range the possible lengths for CA?
Why?

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04-07-2022
Mathematics

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#5 In triangle ABC, AB = 9 and BC = 15. What is the range the possible lengths for CA?
Why?

Sagot :

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```latex\begin{array}{l}\frac{2}{1} \times \frac{3}{10}= \\\frac{8}{1} \times \frac{4}{8}= \\9 \times \frac{3}{9}= \\12 \times \frac{2}{11}= \\3 \times \frac{5}

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Colinspurdleidn Colinspurdleidn · Answer 1 · 2022-07-04T21:19:06-04:00

Colinspurdleidn Colinspurdleidn

04-07-2022

CA must be in the range [15 - 9, 15 + 9] = [6, 24]
For the line segments to form a triangle the length of CA cannot be less the the difference between the other sides or greater than their sum.
At either extreme the three points A, B and C will be co-linear thus forming a triangle with area of zero

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