IDNLearn.com offers expert insights and community wisdom to answer your queries. Discover the reliable solutions you need with help from our comprehensive and accurate Q&A platform.
Sagot :
Answer:
111 cm^2
Step-by-step explanation:
h = 11.4
d = 5 so r (radius) = 2.5
Surface Area of a Cone Formula: πr^2 + πrs
s represents the slant height of the cone, lets represent this with a drawing.
We have the values of h and r, but we don't have the value of s, meaning we have to find it. We can do this by using pythagorean theorem.
a^2 + b^2 = c^2
These three values can come together to create a right triangle which we can seperate from the rest of the diagram, now we can find s.
s = √(11.4^2 + 2.5^2) so s = 11.67
now that we have all of the pieces, we can plug back into the original surface area formula. πr^2 + πrs
π(2.5^2) + π(2.5)(11.67) = 111.29 cm^2 or 111 cm^2


The surface area of the solid cone requiring paint will be 111 square cm.
What is the surface area of a cone?
Let d be the diameter of the base circle, l be the slant height, and h be the height of the cone.
Then the lateral surface area of the cone will be
SA = πrl + πr²
Then the slant height is given as
l² = r² + h²
The exterior of a solid cone is painted. The height of the cone is 11.4 centimeters, and the diameter of its opening is 5 centimeters.
Then the radius of the base circle will be
r = 5 / 2
r = 2.5 cm
The length of the slant height will be
l² = 11.4² + 2.5²
l² = 136.21
l = 11.67
Then the surface area of the solid cone requiring paint will be
SA = π × 2.5 × 11.67 + π × 2.5²
SA = 29.18π + 6.25π
SA = 35.43π
SA = 111.3
SA ≈ 111 square cm
The surface area of the solid cone requiring paint will be 111 square cm.
More about the surface area of a cone link is given below.
https://brainly.com/question/23877107
#SPJ5
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.