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NH3 is produced by the reaction of 0.450 moles of N2 and 0.600 moles of H2 according to the following equation: 2N2 + 3H2 ⟶ 2NH3. (a) How many moles of NH3 are produced? (b) What is the percent yield if 5.52g of NH3 is produced?

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The moles of nitrogen produced is 0.40 moles of ammonia.

The Percent yield of ammonia is 81.2%

What moles of ammonia is produced?

The moles of ammonia produced is obtained from the mole ratio of the reaction.

The mole ratio of hydrogen to nitrogen is 3 : 2

Based on the mole ratio, the limiting reactant is hydrogen.

Moles of nitrogen produced = 0.600 * 2/3 = 0.40 moles of ammonia.

mass of ammonia expected = 0.4 * 17 g = 6.8 g

Percent yield = 5.52/6.8 * 100% = 81.2%

Learn more about mole ratio at: https://brainly.com/question/19099163

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