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Answer:
[tex]\boxed {f(x) = x^{2} - 6x + 1}[/tex]
Step-by-step explanation:
Substituting each x value and checking it corresponds to the table :
x = -6
⇒ f(-6) = (-6)² - 6(-6) + 1
⇒ f(-6) = 36 + 36 + 1
⇒ f(-6) = 73
x = -2
⇒ f(-2) = (-2)² - 6(-2) + 1
⇒ f(-2) = 4 + 12 + 1
⇒ f(-2) = 17
x = 2
⇒ f(2) = (2)² - 6(2) + 1
⇒ f(2) = 4 - 12 + 1
⇒ f(2) = -7
x = 6
⇒ f(6) = (6)² - 6(6) + 1
⇒ f(6) = 36 - 36 + 1
⇒ f(6) = 1
x = 10
⇒ f(10) = (10)² - 6(10) + 1
⇒ f(10) = 100 - 60 + 1
⇒ f(10) = 41