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Use the numbers below to answer the following
question.
6^1, 3^2, 2^3, 1^7
Which shows the numbers ordered from least to
greatest?

Sagot :

Gmanyidn

Power with a natural exponent.

Definition:

[tex]a^2=a\cdot a\\\\a^3=a\cdot a\cdot a\\\\a^4=a\cdot a\cdot a\cdot a\\\vdots\\a^n=\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}[/tex]

also

[tex]a^1=a\\\\a^0=1[/tex]

[tex]6^1=6\\\\3^2=3\cdot3=9\\\\2^3=2\cdot2\cdot2=8\\\\1^7=1[/tex]

therefore

[tex]\huge\boxed{1^7 < 6^1 < 2^3 < 3^2}[/tex]

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