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Answer:
C
Step-by-step explanation:
using the rule of exponents
[tex](\frac{a}{b}) ^{m}[/tex] = [tex]\frac{a^{m} }{b^{m} }[/tex] , then
[tex](\frac{-2}{3}) ^{3}[/tex]
= [tex]\frac{(-2)^{3} }{3^3}[/tex]
= [tex]\frac{-8}{27}[/tex]
= - [tex]\frac{8}{27}[/tex]
Definition:
[tex]a^2=a\cdot a\\\\a^3=a\cdot a\cdot a\\\\a^4=a\cdot a\cdot a\cdot a\\\vdots\\a^n=\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}[/tex]
also
[tex]a^1=a\\\\a^0=1[/tex]
We have
[tex]\left(-\dfrac{2}{3}\right)^3=\left(-\dfrac{2}{3}\right)\cdot\left(-\dfrac{2}{3}\right)\cdot\left(-\dfrac{2}{3}\right)=-\dfrac{2\cdot2\cdot2}{3\cdot3\cdot3}=-\dfrac{8}{27}[/tex]
[tex]\huge\boxed{C:\ -\dfrac{8}{27}}[/tex]