Answered

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The length of a rectangle is 3 yd longer than its width. if the perimeter of the rectangle is 58 yd, find its length and width.

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Answer:

Length = 16 yds

Width = 13 yds

Step-by-step explanation:

P = 2w + 2l

l = w + 3

58 = (2w + 2(w + 3))

58 = 4w + 6

52 = 4w

w = 13

L = w + 3

= 13 + 3

= 16

The length and width of the rectangle are 16,13yd.

The Length and Width of the rectangle can be found as:

Given:

The length of the rectangle is 3yds longer than the width which means length = w+3

and the perimeter is given by 58yd

Let W be the width and L be the length

We know that the perimeter of a rectangle is 2(L+w)

The perimeter of a rectangle is defined as the sum of all the sides of a rectangle

By simplifying we get

2(w+w+3)=58

2(2w+3)=58

2w=29-3

w=13

then the length of the rectangle will be w+3

                                                              13+3 = 16

Learn more about the length, width, and perimeter of a rectangle here:

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