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Please help!!!!! ASAP, If you can, i would love the steps on how to do it!! Thanks

Please Help ASAP If You Can I Would Love The Steps On How To Do It Thanks class=

Sagot :

Devishri1977idn

Answer:

(5,18)  & (-5 , 38)

Step-by-step explanation:

Solutions of linear and quadratic system of equations:

  A linear equation represented by a line in a graph intersect the quadratic equation represented by a parabola zero, one or two times.

f(x) = x² - 2x + 3   -------------------(I)  

f(x) = -2x + 28   ---------------------(II)

x² - 2x + 3 = -2x + 28

x² - 2x + 2x + 3 - 28 = 0

x² - 25 = 0

x²         = 25

         x = √25 = √5*5

        x = ± 5

Plugin x = 5 in equation (II),

                    f(5) = -2*5 + 28

                          = -10 + 28

                          = 18

(5 , 18)

Plugin x = -5 in equation (II),

 f(-5) = -2*(-5) + 28

         = 10 + 28

         = 38

(-5, 38)

                         

Estheridn

Answer:

(5, 18) and (-5, 38)

Step-by-step explanation:

Given system of equations:

1) f(x) = x² - 2x + 3 ⇒ y = x² - 2x + 3

2) f(x) = -2x + 28 ⇒ y = -2x + 28

Solve using the Substitution Method:

Step 1: Substitute the the first equation into the second equation.

⇒ x² - 2x + 3 = -2x + 28

Step 2: Solve for x.

x² - 2x + 3 = -2x + 28 [ Add 2x to both sides. ]

x² - 2x + 2x + 3 = -2x + 2x + 28

⇒ x² + 3 = 28 [ Subtract 28 from both sides. ]

x² + 3 - 28 = 28 - 28

⇒ x² - 25 = 0 [ Factor using the following rule: a² - b² = (a - b)(a + b). ]  

(x - 5)(x + 5) = 0

⇒ x - 5 = 0, x + 5 = 0 [ Solve for the values of x. ]

x - 5 + 5 = 0 + 5, x + 5 - 5 = 0 - 5

⇒ x = 5, x = -5

Step 3: Solve for y.

Substitute the found x-values into one of the given equations.

y = x² - 2x + 3 ⇒ y = (5)² - 2(5) + 3 ⇒ y = 25 - 10 + 3 ⇒ y = 18

y = x² - 2x + 3 ⇒ y = (-5)² - 2(-5) + 3 ⇒ y = 25 + 10 + 3 ⇒ y = 38

The solutions to the system of equations are:

⟹ x₁ = 5, y₁ = 18 ⇒ (5, 18)

⟹ x₂ = -5, y₂ = 38 ⇒ (-5, 38)

Learn more about system of equations here:

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