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Sagot :
There are 16807 number of ways the passengers to be assigned a floor and there are 2520 number of ways the passengers to be assigned a floor but no two passengers are on the same floor.
Given that an elevator starts with five passengers and stops at the seven floors of a building.
From the given information, the total number of floors n=7.
The number of passengers r = 5.
(a) Compute the number of ways that 5 passengers can be assigned to seven floors.
Here, repetition is allowed.
From the known information, if r numbers are selected from n number of observations then the total number of observations that can be drawn from n number of observations is [tex]n^r[/tex].
If 5 passengers can be assigned to seven floors is 7⁵ = 16807.
(b) Compute the number of ways that the passengers to be assigned a floor but no two passengers are on the same floor.
Here, repetition is not allowed.
If 5 passengers can be assigned to seven floors but no two passengers are on the same floor is 7x6x5x4x3 = 2520.
Hence, the number of ways that 5 passengers can be assigned to seven floors is 16807, and the number of ways that the passengers to be assigned a floor but no two passengers are on the same floor is 2520.
Learn about permutation from here brainly.com/question/16554742
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