IDNLearn.com is the perfect place to get detailed and accurate answers to your questions. Our platform is designed to provide quick and accurate answers to any questions you may have.
In order to avoid injury to driver, The force constant of this spring should be 73.82 N/m
Calculation of force constant to this spring:
Here
vertical drop is 15 m.
mass of the car, m= 113 kg
gravitational acceleration, g= -9.8 m/s^2
spring compression before car stops, x= 3.0 m
In order to avoid injury to the driver,
we need to use Hooke's law and Newton's second law:
F(net) = F(x)
m*a=-k*x
here a=g
k= -(m*g) / x
here k is force constant of this spring
substituting the values we get,
k = -(113* -9.8) / (15)
k = 73.8266 N/m
Hence, the force constant of this spring should be 73.82 N/m
learn more about force constant of this spring here:
https://brainly.com/question/15130335
#SPJ4