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The influent BOD5 to a primary settling tank is 345 mg/L. The average flow rate is 0.050 m3/s. If the BOD5 removal efficiency is 30%, how many kilograms of BOD5 are removed in the primary settling tank each day?

Sagot :

The kilograms of BOD5 that are removed in the primary settling tank each day is  447.12 kg.

How to calculate the value?

The BOD5 removed in the primary settling tank each day will be:

= efficiency * influent * average flow rate*24*60*60

The average flow rate is 0.050 m3/s and the BOD5 removal efficiency is 30%,

Influent = 0.345 g/L = 0.000345 kg/L

BOD5 removed in the primary settling tank each day will be:

= 0.3*50*0.000345*24*60*60

= 447.12 kg

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