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Sagot :
The mass of the ethylene glycol used is 14.26 g
What is the freezing point?
The freezing point is the temperature at which a liquid is converted to a solid.
Given that;
ΔT = 0.0°C - ( -4.3°C) = 4.3°C
ΔT = 4.3°C
But we know that
ΔT = k m i
m = ΔT/k i
m = 4.3°C/1.86 °C/m * 1
m = 2.3 m
Now;
Let the mass of ethylene glycol be m
Molar mass of ethylene glycol = 62 g/mol
Mass of solvent = 100.0 g or 0.1 Kg
Then;
2.3= m/62/0.1
2.3 = m/62 * 0.1
m = 2.3 * 62 * 0.1
m = 14.26 g
Learn more about freezing point:https://brainly.com/question/3121416?
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