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Sagot :
The value of m1 is 4.2 kg and value of m2 is 1 kg.
Computation of the value of m1 and m2:
Note:- The value of force is assumed to be 9.70*10^-9 N.
The gravitational force F is given by the formula,
F=Gm1m2 / r^2
where F is the force, G is the universal gravitational constant, m1 and m2 are masses and r is the distance between the masses.
Then the product of the masses is,
m1m2= Fr^2/G
Given F=9.70*10^-9 N, r is 17.0 cm which is equal to 0.17 m.
Therefore product m1m2= 9.70*10^-9 N *(0.17 m)^2 / 6.67*10^(-11) N m^2 kg^-2
m1m2= 4.20 kg^2
m1=4.20 kg^2/m2
The sum of masses is m1+m2=5.20 kg
4.20/m2+m2=5.20
(m2)^2-5.20m2-4.20=0
After solving the above quadratic equation, mass m2 has values 4.2 kg and 1 kg.
By using m2=1 kg, m1 has greater mass 4.2 kg.
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Answer
m1 is equal to 4.2 kg and m2 is equal to 1 kg.
Explanation:
Note:- It is assumed that the force is equal to 9.70*10^(-9) N.
The force of gravitation F is calculated using formula,
F=Gm1m2/r^2
where G is the universal gravitational constant.
Given r=17 cm or 0.17 m and G=6.67*10^(-11) N m^2/ kg^2.
9.70*10^(-9) = 6.67*10^(-11)*m1m2 / (0.17)^2
m1m2=4.20 kg^2
m1=4.20/m2
Given the sum of masses is 5.20 kg.
Therefore,
m1+m2=5.20
4.20/m2+m2=5.20
m2^(2)-5.20m-4.20=0
Solving the quadratic equation, m2 gives values 4.2 and 1.
By using these values, m1 gives values 1 and 4.2 respectively.
But m1 is greater than m2, so m2 =1 kg and m1 = 4.2 kg.
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