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A survey revealed that 36% of people are entertained by reading books, 32% are entertained by watching TV, and 13% are entertained by both books and TV. What is the probability that a person will be entertained by either books or TV

Sagot :

The probability that a person will be entertained by either books or TV is 0.55

What is the required probability?

Express the given percentages as probabilities.

Let the probability of people being entertained by books be represented as

P(A)=0.36

Probability of people entertained by watching TV,

P(B)=0.32

Probability of people entertained by both books and TV,

P(A∩B)=0.13

P(A) + P(B) - P(A and B) is the formula for calculating the either/or probability for overlapping events. This formula is identical to the non-overlapping events, but we need to take the likelihood that the outcomes could occur simultaneously into account.

Thus, the probability of people being entertained by either books or TV is,

P(AUB)=P(A)+P(B)-P(A∩B)

           =0.36+0.32-0.13

           =0.68-0.13

          =0.55          

Learn more about probability here:

https://brainly.com/question/24756209

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