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The margin of error is ±0.1706
The margin of error is a statistical solution for the amount of random sampling error in the survey results.
The 95% confidence interval means from 100 different samples computing a 95% of confidence for each sample. From this, we get the approximate value 95 of the 100 confidence intervals will contain the true mean value.
We have a sample size of n=33
The critical value of the significance level is [tex]\alpha =0.05\\z_{\frac{\alpha }{2} }=1.96[/tex]
Then our sample mean will be 2.5
then the standard deviation is 0.5
from this, we can assume that this is a normal distribution.
then our margin of error will be
[tex]E=[/tex]±[tex]z_{\frac{\alpha }{2} }\frac{deviation}{\sqrt{n} }[/tex]
⇒[tex]E=[/tex]±[tex](1.96)\frac{0.5}{\sqrt{33} }\\[/tex]
≅±0.1706 is the margin of error.
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