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Sagot :
The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time
z-score is the number of standard deviations from the mean value of the reference population
99%=0.99
The z-value associate with 0.99 is 2.33:
2.33 = (X - 12425) / 595:
X - 12425 = 2.33 * 595
X = (2.33 * 595) + 12425
X = 138111
Therefore, The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time
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