IDNLearn.com offers a user-friendly platform for finding and sharing knowledge. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
Sagot :
The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time
z-score is the number of standard deviations from the mean value of the reference population
99%=0.99
The z-value associate with 0.99 is 2.33:
2.33 = (X - 12425) / 595:
X - 12425 = 2.33 * 595
X = (2.33 * 595) + 12425
X = 138111
Therefore, The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time
Learn more about the Manufacturer here
https://brainly.com/question/19584679
#SPJ4
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.
