Find detailed and accurate answers to your questions on IDNLearn.com. Ask your questions and receive comprehensive and trustworthy answers from our experienced community of professionals.

What is the smallest positive integer $n$ for which $n^2$ is divisible by 18 and $n^3$ is divisible by 640

Sagot :

The smallest positive integer n for which n^2 is divisible by 18 and n^3 is divisible by 640 is 120

The modulo (or "modulus" or "mod") is the remainder after dividing one number by another.

The smallest integer is 120, since:

[tex]120^{2}[/tex] mod 18 = 0, (reminder after dividing [tex]120^{2}[/tex] by 18 is 0) and

[tex]120^{3}[/tex] mod 640 = 0 (reminder after dividing [tex]120^{3}[/tex] by 18 is 0)

Hence, The smallest positive integer n for which n^2 is divisible by 18 and n^3 is divisible by 640 is 120.

Learn more about Divisibility here

https://brainly.com/question/8226236

#SPJ4