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The store currently has seven rackets of each version. What is the probability that all of the next ten customers who want this racket can get the version they want from current stock

Sagot :

The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821

How to solve?

Given: currently has seven rackets of each version.

Then the probability that the next ten customers get the racket they want is P(3≤X≤7)

Why P(3≤X≤7)?

Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.

X ~ Binomial (n = 10, p = 0.6)

P(3≤X≤7)  = P(X≤7) - P(X≤2)

From Binomial Table:

               = 0.8333 - 0.012

               = 0.821

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