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Find the polar equation of the conic with focus at the pole, directrix y=3, and eccentricity of 2. a. r= 6/1+2 sin theta b. r= 6/1-2 sin theta c. r= 3/ 1- 2 cos theta d. r= 1/3+2 cos theta

Sagot :

The required polar equation of a conic is given be: [tex]r = \frac{6}{1-2sin\Theta }[/tex]. option b is correct.

For a conic we have directrix = 3 and eccentricity = 2

What is polar equation?

Polar equation can be identified as of the form of x= a+b.sinФ.
Which contain simple variable along with trigonometric operators.

Here,

Standard polar equation for the conic is given as,

    [tex]r=\frac{ep}{1-esin\theta}[/tex]  
By putting given values
[tex]r = \frac{6}{1-2sin\Theta }[/tex].
Thus, the required polar equation for the conic is  [tex]r = \frac{6}{1-2sin\Theta }[/tex].

Learn more about polar equation here:
https://brainly.com/question/2094876

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