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Sagot :
Fission of 1 kg of element B releases 2941 times as much energy as burning 1 kg of element A
How to compare the energy released?
The given parameters are:
Energy A = 5.1 * 10^7
Energy B = 1.5 * 10^11
The amount of energy B in proportion to energy A is calculated as
Proportion = Energy B/Energy A
So, we have:
Proportion = (1.5 * 10^11)/(5.1 * 10^7)
Divide 1.5 by 5.1
Proportion = 0.2941 * 10^11/10^7
Divide 10^11 by 10^7
Proportion = 0.2941 * 10^4
Evaluate
Proportion = 2941
Hence, fission of 1 kg of element B releases 2941 times as much energy as burning 1 kg of element A
Read more about quotient at:
https://brainly.com/question/673545
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