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Every weekend me and my brother and my cousin go outside to play basketball and when i was the one who will shoot the ball to the ring i used the things i learned in math so I use SOH-CAH-TOA in measuring it. I want to measure the distance between me and the basketball ring. Supposed the height of the ring is 8ft from the ground and the distance between me and the basketball ring horizontally is 11.5 ft, and the angle of elevation from the ground is 50 degrees, now what is the distance of me and the ring?

Let x be the distance between me and the ring

need urgent answers with equation

Every Weekend Me And My Brother And My Cousin Go Outside To Play Basketball And When I Was The One Who Will Shoot The Ball To The Ring I Used The Things I Learn class=

Sagot :

Johnny837idn

Answer:

[tex]x=14[/tex]

Step-by-step explanation:

1) Since we know two of the sides of that right-angled triangle, we can use the Pythagorean Theorem to find x. His theorem is: [tex]c^2 = a^2 + b^2[/tex].

Substitute the values into the formula above.

Let x = c

[tex]c^2 = 8^2 + 11.5^2\\c^2 = 196.25\\c= \sqrt{196.25}\\c=14[/tex]

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