IDNLearn.com offers a unique blend of expert answers and community insights. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.
Sagot :
The Answer to the question is 124.66 grams approximately.
It is given that H₂ will react completely
Molar mass of H₂ = 2 × 1 = 2 gm/mol
Given mass of H₂ = 22 gm
Moles of H₂ reacting = given mass of H₂ / molar mass of H₂
Moles of H₂ reacting = 22 / 2 moles = 11 moles
So, 11 moles of H₂ are taking part in reaction.
The Balanced chemical reaction is as follows as:
N₂ + 3 H₂ → 2 NH₃
It is clear from the reaction that 3 moles of H₂ are making 2 mole of NH₃
3 moles of H₂ → 2 mole of NH₃
1 moles of H₂ → 2/3 mole of NH₃
11 moles of H₂ → (2/3)×11 mole of NH₃
11 moles of H₂ → 22/3 mole of NH₃
So, 11 moles of H₂ will make 22/3 mole of NH₃
22/3 mole NH₃ = mass formed NH₃ / molar mass of NH₃
mass formed NH₃ = 22/3 × molar mass of NH₃
mass formed NH₃ = 22/3 × 17
mass formed NH₃ = 22/3 × 17
mass formed NH₃ = 124.66 grams (approximately)
124.66 grams of NH₃ will be formed.
So, approximately 124.66 grams of NH₃ is formed from 22 grams of H₂.
Learn more about Stoichometry here:
brainly.com/question/25829169
#SPJ10
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
