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What mass of AI2O3 forms from 16 g O2 and excess AI?

Sagot :

Ayesha67idn

Answer:

2Al+1.5O2→Al2O3

Thus, 2 mol of Al combine with 1.5 mol of oxygen to form 1 mol of Al2O3.

2 mol of Al corresponds to 2×27=54 g.

Thus, the weight of Al used in the reaction is 54 g.

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