Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Discover in-depth and trustworthy answers from our extensive network of knowledgeable professionals.
Sagot :
(a) The unknown charge kept at distance 0.250m directly below -0.450 charge is 2.315 x 10⁻¹² C.
(b) The magnitude of the force is 29.16 x 10¹² N.
What is electrostatic force?
The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.
F = kq₁q₂/r²
where k = 9 x 10⁹ N.m²/C²
Given is a negative charge -0.450 exerts an upward 0.150N force on an unknown charge 0.250m directly below it .
In equation of the magnitude of force, only the magnitude of charges are taken.
Substituting the values into the expression ,we get the charge
0.150 = (9 x 10⁹ x 0.450x q)/ (0.25)²
q = 2.315 x 10⁻¹² C
Thus, the magnitude of the unknown charge is 2.315 x 10⁻¹² C.
b)Let the unknown charge be 0.450C to exert on -450C.
Substituting the values into the expression ,we get the electrostatic force
F = kq₁q₂/r²
F = (9 x 10⁹ x 0.450x 0.450)/ (0.25)²
q = 2.315 x 10⁻¹² C
Thus, the magnitude of the force is 29.16 x 10¹² N.
Learn more about electrostatic force.
https://brainly.com/question/9774180
#SPJ1
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.
