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What is the equivalent resistance of a circuit that contains three 10.0 Ω
resistors connected in series to a 6.0 V battery?

Ο A. 0.600 Ω
Ο Β. 60.0 Ω
Ο C. 16.0 Ω
Ο D. 30.0 Ω


Sagot :

Answer:

O D.30.0 Ω

Explanation:

this is the correct answer!

Question :

  • What is the equivalent resistance of a circuit that contains three 10.0 Ω resistors connected in series to a 6.0 V battery?

Options given :

  • A. 0.600 Ω
  • Β. 60.0 Ω
  • C. 16.0 Ω
  • D. 30.0 Ω

Solution :

As we know that,

When a circuit is connected in series resistance is calculated by :

  • Rs = R1 + R2 + R3 .... Rn

Here,

  • R is resistance

As a circuit contains three resistors. So R1 , R2 and R3 would be :

  • R1 = 10 Ω
  • R2 = 10 Ω
  • R3 = 10 Ω

Now,

>> Rs = 10 + 10 + 10

>> Rs = 30 Ω

Therefore,

  • Option D is correct.