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The volume of the baseball roundibg off to nearest whole number is 14 cube inches.
If radius of a sphere is r and the volume of that spherical figure is given by V then,
[tex]V=\frac{4}{3}\pi r^3[/tex]
So in the problem the object is a baseball which is a sphere for sure.
Given that the diameter of that baseball is 3 inches.
So the radius of that baseball is given by = 3/2 = 1.5 inches.
Hence the volume of that base ball is
[tex]=\frac{4}{3}\pi\times(1.5)^3 \approx 14.1372 \approx 14[/tex]
Thus the volume of the baseball rounding off to nearest whole number is given by 14 cube inches.
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