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Sagot :
Theoretical yield produced is 31.8 gram and the percentage yield is 62.27%.
The zinc (Zn) is more reactive than lead (Pb). So that zinc loses electrons more easily than lead .
And the electrons of Zn are transfer to lead in this reaction .
This question is a limiting reactant question .
And For limiting reactant questions so that we need to determine that how much product can be produced by all reactant .
Zinc and Lead (II) nitrate react to form Zinc Nitrate and Lead.
Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb
Now we have- Weight of Pb(NO₃)₂ = 49.5 g
molar mass of Pb(NO₃)₂ = 331.2 g
now moles of Pb(NO₃)₂ = 49.5 ÷ 331.2 = 0.15 moles
Moles of Pb consumed = 1 × 0.15 = 0.15
moles mass of Pb consumed = 0.15 × 207.2 = 31.8 gm
Here Zn is in excess so that lead(II) nitrate is a limiting reactant.
(a) Theoretical yield of lead -
moles of Pb produced = 0.15 × 1 = 0.15 moles
molar mass of Pb = 207.2g
mass of Pb produced in reaction = 0.15 × 207.2 = 31.08 g
theoretical yield = 31.8 gram
(b) After separating the lead by filtration -
obtained lead = 19.8gm
Percentage yield = 19.8 ÷ 31.8 ×100 = 62.27%
so that after separating the lead the percentage yield is 62.27%.
So, After applying the concepts of stoichiometric method the theoretical yield produced came out to be 31.8 gram and the percentage yield came out to be 62.27%.
Learn more about theoretical yield here:
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