Get insightful responses to your questions quickly and easily on IDNLearn.com. Ask anything and receive prompt, well-informed answers from our community of knowledgeable experts.

A balloon with a volume of 2.0 l at 25°c is placed in a hot room at 35°c. the pressure on the balloon is constant at 1.0 atm. formula to use: v1 t1 = v2 t2 how does the volume of the balloon change after moving it to the hot room?

Sagot :

The volume increases and the final volume is 2.1 L

Why volume increases?

The volume of a gas is directly related to the heat and pressure. If temperature increases, volume increases.

If pressure increases, volume decreases

Based on Boyle's law,

The absolute temperature of a gas is directly proportional to the volume of the gas.

As the balloon change increases its temperature, the volume increases

The Boyle's equation is:

V₁T₂ = V₂T₁

Where,

  • V is volume
  • T is absolute temperature of 1, initial state and 2, final state of the gas.

Replacing :

V₁ = 2.0L

T₂ = 35°C + 273.15 = 308.15K

V₂ = ?

T₁ = 25°C + 273.15 = 298.15 K

2.0L x 308.15 K = V₂ x 298.15 K

2.1 L = V₂

Final volume is 2.1L

Hence, The volume increases and the final volume is 2.1 L

Learn more about gas laws here ;

https://brainly.com/question/12669509

#SPJ1

Answer:

increases, 2.1

Explanation:

I got it right.

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.