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determine the slope of a line that is parrallel to the equation 3x + 6y =18

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SOLVING

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

Determine the slope of a line that is parallel to the equation [tex]\bf{3x+6y=18}[/tex].

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

First we should divide the whole equation by 6,

[tex]\bf{\dfrac{3}{6}x+\dfrac{6}{6}y=\dfrac{18}{6}}[/tex] | simplify

[tex]\bf{\dfrac{1}{2}x+y=3}[/tex] | subtract 1/2 x

[tex]\bf{y=-\dfrac{1}{2}x+3[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\bf{Result:}[/tex]

            [tex]\bf{=Slope-\dfrac{1}{2}[/tex]

[tex]\boxed{\bf{aesthetic\not101}}[/tex]

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