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A plane flies at 350 mph in the direction 40° north of east, with a wind blowing at 40 mph in the direction 30° south of east. what is the plane’s drift angle?

Sagot :

Lets simplify the given problem,

The speed with which the plane flies = 350 mph

The direction of flight of the plane = N 40° E

The speed with which the wind blows = 40 mph

The direction in which the wind blows = S 40° E

Therefore, we have;

The resolution of the components of the motion of the plane, given as follows;

= 350 × sin(40°)·i + 350 × cos(40°)·j

The resolution of the components of the motion of the wind, given as follows;

= 40 × sin(40°)·i - 40 × cos(40°)·j

The resultant motion of the plane is given as follows;

= 262.563·i + 254.435·j

The direction of motion of the plane = tan⁻¹(262.563/254.435) ≈ N 45.9° E

Therefore, the plane's drift = Plane's Track - Plane's Heading  = N 45.9° E - N 40° E ≈ 5.9° ≈ 5.89°

Drift Angle of the plane is 5.89 degree.

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