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find two consecutive even integers such that 8 times the first equals 7 times the second​

Sagot :

Answer:

Step-by-step explanation:

let the consecutive even integers be 2x,2x+2

8×2x=7(2x+2)

16x=14x+14

16x-14x=14

2x=14

x=14/2=7

so numbers are 2×7,2×7+2

or

14,16

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