If the angles of a convex octagon are [tex]2x+6,x+13,2x-1,2x+12,2x-17,3x-4,3x-10,4x.[/tex] then the smallest angle is 21°.
Given The exterior angles of convex octagon are [tex]2x+6,x+13,2x-1,2x+12,2x-17,3x-4,3x-10,4x.[/tex]
and we have to find the value of smallest angle.
The sum of the angles of a convex octagon is 360°
so to calculate the smallest angle we need to find out the value of x first and which is calculated by summing up all the exterior angles and put them equal to 360.
(2x+6)+(x+13)+(2x-1)+(2x+12)+(2x-17)+(3x-4)+(3x-10)+4x=360
2x+6+x+13+2x-1+2x+12+2x-17+3x-4+3x-10+4x=360
2x+x+2x+2x+2x+3x+3x+4x+6+13-1+12-17-4-10=360
19x-1=360
19x=360+1
19x=361
x=361/19
x=19
Putting the value of x in all the angles and we will find the following:
2x+6=2*19+6=44
x+13=19+13=32
2x-1=2*19-1=37
2x+12=2*19+12=50
2x-17=2*19-17=21
3x-4=3*19-4=51
3x-10=3*19-10=47
4x=4*19=76
Hence among all the exterior angles the smallest angle is 21°.
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