When t is between 2 and 5, the ball will be above 10 feet.so answer is:
C. 2 ≤ t ≤ 5
Given, height h(t) = ₋t² ₊ 7t
At what values of time t is the ball 10 feet above the ground = ?
To find out the time we need to set up an inequality.
Inequality expression is given as = ₋t² ₊ 7t ≥ 10
= ₋t² ₊ 7t ₋ 10 ≥ 0
= ₋(t² ₋ 7t ₊ 10) ≥ 0
= t² ₋ 7t ₊10 ≥ 0
Now, factorize the expression and get the factors.
= t² ₋ 2t ₋ 5t ₊ 10 ≥ 0
=t(t ₋ 2) ₋ 5(t ₋ 2) ≥ 0
=(t ₋ 2) (t ₋ 5) ≥ 0
Hence t value ranges from t = 2 and 5.
As a result, when t is between 2 and 5 seconds, the ball will be farther than 10 feet, 2 ≤ t ≤ 5
Learn more about "Inequality equations" here-
brainly.com/question/25275758
#SPJ10
