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. 40% of students passed 90% students attended class 30% both passed and attended class martin was selected at random he attend class daily determine the probability that he passed the exam

Sagot :

Varshamittal029idn

Probability that Martin passed the exam when he attend the class daily is given by 1/3.

Probability is the possibility to occurrence of an event.

In other words, Probability is the ratio of number of favorable cases under an event to total number of cases under that event.

Let P be the event that Martin passed the exam and A be the event that he attend the class daily.

Given that,

40% of students passed tbe exam.

The probability to pass the exam is given by,

[tex]P(P)=40%=\frac{40}{100}=\frac{4}{10}[/tex]

90% students attend the class daily

probability to attend the class daily is given by,

[tex]P(A)=90%=\frac{90}{100}=\frac{9}{10}[/tex]

30% student both passed the exam and attended class

So probability to both passed the exam and attend the class is given by,

[tex]P(P\cap A)=30%=\frac{30}{100}=\frac{3}{10}[/tex]

Now conditional probability that Martin will passed the exam if he attend class daily is given by,

[tex]P(P|A)=\frac{P(P\cap A)}{P(A)}=\frac{\frac{3}{10}}{\frac{9}{10}}=\frac{3}{9}=\frac{1}{3}[/tex]

Hence the required pobability that Martin passed the exam when he attend the class daily is given by 1/3.

Learn more about Conditional Probability here -

https://brainly.com/question/10739997

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