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The perimeter of a triangle is 44cm. One side is 4cm shorter than the second side and twice as long as the third side. Find the length of each side of the triangle.

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Varshamittal029idn

The 1st, 2nd, and 3rd sides of the triangle are 16, 20, and 8 respectively.

Given that the perimeter of the triangle is 44 cm.

Let us consider a side 's' which is 4 cm shorter than the second side.

That means the second side is 4 cm longer than s, hence the second side is s+4 cm in length.

We also have that the side of length s is of length twice as long as the third side.

Hence, the length of the third side is half that of s so, it is of length s/2.

Hence, at the end 44=s+(s+4)+(s/2)=s(2+1/2)+4

⇒ s(5/2)=40

⇒ s=8*2=16

So, the 1st, 2nd, and 3rd sides of the triangle are 16, 20, and 8 respectively.

Learn more about triangles here-

brainly.com/question/2773823

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