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How much heat will be absorbed by a 66.3 g
piece of aluminum (specific heat = 0.930 J/
g. °C) as it changes temperature from 23.0°C
to 67.0°C?

Sagot :

Indrawboyidn

Q=mcΔt

Q=66.3 x 0.93 x (67-23)

Q=2712.996 J

AǫᴜᴀWɪᴢidn

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]

[tex] \textsf{Q = heat evolved/absorbed = ??} [/tex]

[tex] \textsf{m = mass in gram = 66.3 g} [/tex]

[tex] \textsf{s = specific heat = 0.930 J/g °C} [/tex]

[tex] \textsf{ΔT = change in temp = 67 - 23 =44°C} [/tex]

[tex] \large\textsf{Find Q : } [/tex]

[tex]\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2713 \: \: joules[/tex]

[tex]\qquad \tt \rightarrow \:Q= 2.713 \: \: kj[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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