Experience the power of community-driven knowledge on IDNLearn.com. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.

Find the length of the short leg on the following right triangle.

Find The Length Of The Short Leg On The Following Right Triangle class=

Sagot :

60+90+ angle U = 180 {sum of angle of triangle}

or, 150+ U= 180

or, angle U = 30°

From here we got that ,

angle U is smallest.

We know that, side opposite to the shortest angle is shortest side. So , short leg is side PM

In right angled triangle PMU,

hypotenuse(h) = 10

angle theta = 60°

perpendicular (PM)= ?

NOW,

sin theta = Perpendicular/ hypotenuse

or, sin 60° = P/10

[tex] \\or \frac{ \sqrt{3} }{2} = p \div 10[/tex]

[tex] or\frac{10 \sqrt{3} }{2} = p[/tex]

[tex]or \: 5 \sqrt{3 } = p[/tex]

Therefore,

[tex]short \: leg = 5 \sqrt{3} [/tex]