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find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (ignore friction forces etc.- also remember Work is the inner product of Force and direction vectors. Furthermore remember gravity is a force acting in the downward direction)

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The work done in pushing the box is 64000 lb-ft²/s²

How to calculate the work done by the person?

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

https://brainly.com/question/25970931

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