Nicolekerubo10idn
Answered

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7. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7, find the smallest possible value of m. (3 marks)
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Sagot :

Devishri1977idn

Answer:

187

Step-by-step explanation:

Least common multiple:

To find the required number,

  1. Find the LCM of 30 , 36  and 45
  2. Then add 7 to the LCM

30 =  2 * 3 * 5

36 = 2 * 2 * 3 * 3 = 2² * 3²

45 = 2 * 3 * 3 = 2 *3²

LCM = 2² * 3² * 5

        = 4 * 9 * 5

        = 180

Required number = 180 + 7

                             = 187

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