Get expert advice and community support for your questions on IDNLearn.com. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.
The equation to model the situation is [tex]\mathbf{y = \dfrac{k}{x^2}}[/tex]. The constant for the variation is 2250.
The intensity of light from a lantern varies inversely to the square of the distance from the lantern.
From the given information:
Then:
[tex]\mathbf{y \alpha \dfrac{1}{x^2} }[/tex]
[tex]\mathbf{y = \dfrac{k}{x^2} }[/tex] here, k = constant.
2.
If y = 90 W/m² when the distance x = 5m
Then:
[tex]\mathbf{90 = \dfrac{k}{(5)^2}}[/tex]
k = 90 × 25
k = 2250
c.
The equation to model the situation by using the constant variation is:
[tex]\mathbf{y = \dfrac{2250}{x^2}}[/tex]
d.
If the light intensity y = 40, then x is determined as:
[tex]\mathbf{40 = \dfrac{2250}{x^2}}[/tex]
[tex]\mathbf{x = \sqrt{\dfrac{2250}{40}}}[/tex]
x = 7.5 m
e.
The light is needed in (225 × 1000)m = 225000 km of illumination.
f.
The lantern required for the new light estimation is:
y = 2250/225000
y = 0.01 intensity
Therefore, we can conclude that to get an intensity of 1 W/m², we need to put 100 lanterns.
Learn more about intensity of light here:
https://brainly.com/question/19791748
#SPJ1