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Sagot :
Answer:
See below
Explanation:
You have to heat the calorimeter to 100 C from 20 C
this will take .20 kg * 390 j /kg-C * 80 C = 6240 j
You have to heat the mass of water to boiling point (100 C ) from 20C
this will take
.50 kg * 4182 j/kg-C * 80 = 167,280 j
AND you have to add enough heat to boil off .03 kg of water:
.03 kg * (2260000 j/kg-C ) = 67,800 j
Power = joules / sec = (6240 + 167280 + 67800) / 274.8 = 878 watts
Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....
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