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Answer:
A
Explanation:
Phosphorus has an electron configuration of 1s2 2s2 2p6 3s2 3p3. Another way to write that is [Ne] 3s2 3p3. The [Ne] represents the fact that the beginning of phosphorus' electron configuration is the same as Neon's. so if you add all the superscripts they will give you 15. we didn't use choice d because we have to make the last p halffilled(3, half of the total electron held in p shell ) when we make "s shell 1 " not make it 4 because we are transfering that 1 electron .but nevertheless the correct answer is A.